If the daily water usage is 750,000 gallons and a chlorinator dosage is set at 4.0 mg/L, what should the gas chlorinator feed rate be set at in pounds per day?

To determine the gas chlorinator feed rate in pounds per day, given the daily water usage and the chlorinator dosage, it's essential to convert the dosage from mg/L to pounds.

Start by recognizing that 1 mg/L is equivalent to 1 pound per million gallons. In this scenario, with a daily usage of 750,000 gallons, the conversion process would work as follows:

1. First, calculate how many million gallons are in 750,000 gallons: [ 750,000 , \text{gallons} = 0.75 , \text{million gallons} ]

2. Next, since the dosage is set at 4.0 mg/L, we can find out how many pounds are needed for 0.75 million gallons: [ \text{Pounds needed} = \text{Dosage (mg/L)} \times \text{Usage (million gallons)} = 4.0 , \text{mg/L} \times 0.75 , \text{million gallons} = 3.0 , \text{pounds} ]

3. To convert this into a daily feed rate, it is necessary to