If a dosage of 4.0 mg/l is added to 750,000 gallons of water, how many pounds of chlorine are needed?

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To calculate the amount of chlorine in pounds required for a dosage of 4.0 mg/l in 750,000 gallons of water, you can follow these steps:

Convert gallons to liters: There are approximately 3.785 liters in a gallon, so first convert 750,000 gallons to liters: [

750,000 \text{ gallons} \times 3.785 \text{ liters/gallon} = 2,839,125 \text{ liters} ]

Calculate the amount of chlorine in milligrams: Since the dosage is in mg/l, we multiply the concentration of chlorine by the total volume in liters to find the total amount in milligrams: [ 4.0 \text{ mg/l} \times 2,839,125 \text{ liters} = 11,356,500 \text{ mg} ]
Convert milligrams to pounds: There are 453,592 milligrams in a pound, so convert the total milligrams to pounds: [ \frac{11,356,500 \text{ mg}}{453,592 \text{ mg/pound}}