How many pounds of 70% chlorine (HTH) are needed to equate to 9.0 pounds of 100% chlorine?

Prepare for the Texas Commission on Environmental Quality (TCEQ) Class C Water License Exam. Utilize flashcards, multiple choice questions, and in-depth explanations. Equip yourself with the skills to succeed!

To determine how many pounds of 70% chlorine are needed to equal 9.0 pounds of 100% chlorine, you first need to recognize that 70% chlorine means that only 70% of the weight of this product is actual chlorine.

To find out how much 70% chlorine is required, you can set up the equation based on the concentration and the amount of chlorine needed. The calculation involves dividing the total amount of pure chlorine required by the concentration of the chlorine solution.

For 9.0 pounds of pure chlorine, the formula is:

Amount of 70% chlorine = Amount of pure chlorine / Concentration

So, you take:

Amount of 70% chlorine = 9.0 pounds / 0.70

Calculating this gives:

Amount of 70% chlorine = 12.857 pounds

When rounded, this figure typically is presented as 12.85 pounds. This means that to achieve the equivalent of 9.0 pounds of pure chlorine, you need approximately 12.85 pounds of 70% chlorine.

This approach directly compares the required pure chlorine against the effective concentration of the chlorine you have, ensuring that the resulting weight provides the necessary amount of active chlorine.

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